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NEET CHEMISTRYAminesMedium

Question

The reaction of propanamide with ethanolic sodium hydroxide and bromine will give:

A

Ethylamine

B

Methylamine

C

Propylamine

D

Aniline

Step-by-Step Solution

The reaction of a primary amide with bromine in an aqueous or ethanolic solution of sodium hydroxide is known as the Hoffmann bromamide degradation reaction. This is a method for the preparation of primary amines. A characteristic feature of this reaction is that the amine formed contains one carbon atom less than the starting amide (the carbonyl carbon is lost as sodium carbonate).

Chemical Equation: CH3CH2CONH2 (Propanamide)+Br2+4NaOH→ΔCH3CH2NH2 (Ethylamine)+Na2CO3+2NaBr+2H2OCH_3CH_2CONH_2 \text{ (Propanamide)} + Br_2 + 4NaOH \xrightarrow{\Delta} CH_3CH_2NH_2 \text{ (Ethylamine)} + Na_2CO_3 + 2NaBr + 2H_2O

Since the reactant, propanamide, has 3 carbon atoms, the resulting primary amine will have 2 carbon atoms, which is Ethylamine.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Amines. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYAminesreactionpropanamideethanolicsodiumhydroxide

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The products formed when Aniline reacts with $Br_2$ water, and $NaNO_2/HCl$ will be, respectively:

A.p-Bromoaniline; p-Chloroaniline
B.2,4,6-Tribromoaniline; p-Chloroaniline
C.2,4,6-Tribromoaniline; Benzenediazonium chloride
D.p-Bromoaniline; Benzenediazonium chloride
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Aniline gives a set of the following reactions that yielded a coloured product 'Y'. The structure of 'Y' is: (Note: Reaction scheme is missing from the provided text)

A.Option 1
B.Option 2
C.Option 3
D.Option 4
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The structure of C in the below-mentioned reaction is: (Note: Reaction scheme is missing from the provided text)

A.Option 1
B.Option 2
C.Option 3
D.Option 4
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What results from the electrolytic reduction of nitrobenzene in a highly acidic medium?

A.p-Aminophenol
B.Azoxybenzene
C.Azobenzene
D.Aniline
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The reagent required to convert acetamide into methyl amine is:

A.$NaOH/Br_2$
B.Sodalime
C.Hot conc. $H_2SO_4$
D.$PCl_5$
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D is N-methyl aniline in the given below sequence of reaction: $A \xrightarrow{\text{reduction}} B \xrightarrow{CHCl_3/KOH} C \xrightarrow{\text{reduction}} D$. Structure of A can be:

A.Option 1 (Missing)
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D.Option 4 (Missing)
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Which of the following statements about primary amines is false?

A.Alkyl amines are stronger bases than aryl amines
B.Alkyl amines react with nitrous acid to produce alcohols
C.Aryl amines react with nitrous acid to produce phenols
D.Alkyl amines are stronger bases than ammonia
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What is the correct order of the methyl-substituted amines' basic strength in an aqueous solution?

A.$CH_3NH_2 > (CH_3)_2NH > (CH_3)_3N$
B.$(CH_3)_2NH > CH_3NH_2 > (CH_3)_3N$
C.$(CH_3)_3N > CH_3NH_2 > (CH_3)_2NH$
D.$(CH_3)_2NH > (CH_3)_3N > CH_3NH_2$
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