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NEET CHEMISTRYHydrocarbonsMedium

Question

Using anhydrous AlCl3\text{AlCl}_3 as a catalyst, which one of the following reactions produces ethylbenzene (PhEt)?

A

CH3-CH=CH2+C6H6\text{CH}_3\text{-CH=CH}_2 + \text{C}_6\text{H}_6

B

H2C=CH2+C6H6\text{H}_2\text{C=CH}_2 + \text{C}_6\text{H}_6

C

H3C-CH3+C6H6\text{H}_3\text{C-CH}_3 + \text{C}_6\text{H}_6

D

H3C-CH2OH+C6H6\text{H}_3\text{C-CH}_2\text{OH} + \text{C}_6\text{H}_6

Step-by-Step Solution

Ethylbenzene can be prepared by the Friedel-Crafts alkylation of benzene. While alkyl halides are typically used, alkenes can also serve as the alkylating agent in the presence of a Lewis acid catalyst such as anhydrous AlCl3\text{AlCl}_3 (often with a trace of HCl\text{HCl} to generate the initial electrophile). Thus, the reaction of benzene (C6H6\text{C}_6\text{H}_6) with ethene (H2C=CH2\text{H}_2\text{C=CH}_2) produces ethylbenzene.

  • Option A: Reaction with propene (CH3-CH=CH2\text{CH}_3\text{-CH=CH}_2) would yield isopropylbenzene (cumene) .
  • Option C: Alkanes like ethane (H3C-CH3\text{H}_3\text{C-CH}_3) do not undergo this reaction.
  • Option D: While alcohols can act as alkylating agents, they typically require a protic acid like H2SO4\text{H}_2\text{SO}_4, as the water byproduct would complex with and deactivate a Lewis acid like AlCl3\text{AlCl}_3.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Hydrocarbons. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYHydrocarbonsanhydroustextalclcatalystfollowingreactions

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