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NEET CHEMISTRYAldehydes, Ketones and Carboxylic AcidsMedium

Question

When m-chlorobenzaldehyde is treated with 50% KOH solution, the product(s) obtained is (are):

A

m-Chlorobenzyl alcohol and potassium m-chlorobenzoate

B

m-Chlorobenzoic acid and m-chlorobenzyl alcohol

C

m-Hydroxybenzaldehyde and m-chlorobenzyl alcohol

D

m-Chlorobenzyl alcohol and m-chlorophenol

Step-by-Step Solution

The reaction of m-chlorobenzaldehyde with a concentrated alkali (50% KOH) is an example of the Cannizzaro reaction. Aldehydes that do not have an α\alpha-hydrogen atom (like benzaldehyde and its derivatives) undergo self-oxidation and reduction (disproportionation) on heating with concentrated alkali.

One molecule of the aldehyde is reduced to the corresponding alcohol (m-chlorobenzyl alcohol), and another molecule is oxidised to the corresponding carboxylic acid salt (potassium m-chlorobenzoate).

2 m-Cl-C6H4CHO+KOH→m-Cl-C6H4CH2OH+m-Cl-C6H4COO−K+2 \text{ m-Cl-C}_6H_4CHO + KOH \rightarrow \text{m-Cl-C}_6H_4CH_2OH + \text{m-Cl-C}_6H_4COO^-K^+

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Aldehydes, Ketones and Carboxylic Acids. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYAldehydes, Ketones and Carboxylic Acidsmchlorobenzaldehydetreatedsolutionproductsobtained

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