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NEET generalGeneralEasy

Question

A carbon resistor of (47 ± 4.7) k is to be marked with rings of different colours for its identification. The colour code sequence will be

A

Yellow – Green – Violet – Gold

B

Yellow – Violet – Orange – Silver

C

Violet – Yellow – Orange – Silver

D

Green – Orange – Violet – Gold

Step-by-Step Solution

(47±4.7) kΩ=47×103±10%(47 \pm 4.7) \text{ k}\Omega = 47 \times 10^3 \pm 10\%

Exam Context & Concepts Covered

This question aligns with the NEET general syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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