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NEET generalGeneralMedium

Question

A metallic rod of mass per unit length 0.5 kg m−10.5 \text{ kg m}^{-1} is lying horizontally on a smooth inclined plane which makes an angle of 30∘30^{\circ} with the horizontal. The rod is not allowed to slide down by flowing a current through it when a magnetic field of induction 0.25 T0.25 \text{ T} is acting on it in the vertical direction. The current flowing in the rod to keep it stationary is

1

14.76 A

2

5.98 A

3

7.14 A

4

11.32 A

Step-by-Step Solution

For equilibrium, mgsin⁡30∘=IBcos⁡30∘mg \sin 30^{\circ} = IB \cos 30^{\circ}. Thus, I=mgBtan⁡30∘=0.5×9.80.25×3=11.32 AI = \frac{mg}{B} \tan 30^{\circ} = \frac{0.5 \times 9.8}{0.25 \times \sqrt{3}} = 11.32 \text{ A}.

Exam Context & Concepts Covered

This question aligns with the NEET general syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

generalmetalliclengthhorizontallysmoothinclined

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