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NEET generalGeneralMedium

Question

A sample of 0.1 g of water at 100°C and normal pressure (1.013 × 105 Nm–2) requires 54 cal of heat energy to convert to steam at 100°C. If the volume of the steam produced is 167.1 cc, the change in internal energy of the sample, is

A

42.2 J

B

42.2 J

C

104.3 J

D

84.5 J

Step-by-Step Solution

ΔQ=ΔU+ΔW\Delta Q = \Delta U + \Delta W

⇒54×4.18=ΔU+1.013×105(167.1×10−6−0)\Rightarrow 54 \times 4.18 = \Delta U + 1.013 \times 10^5(167.1 \times 10^{-6} - 0)

⇒ΔU=208.7 J\Rightarrow \Delta U = 208.7 \text{ J}

Exam Context & Concepts Covered

This question aligns with the NEET general syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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