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NEET generalGeneralMedium

Question

A tuning fork is used to produce resonance in a glass tube. The length of the air column in this tube can be adjusted by a variable piston. At room temperature of 27°C two successive resonances are produced at 20 cm and 73 cm of column length. If the frequency of the tuning fork is 320 Hz, the velocity of sound in air at 27°C is

A

350 m/s

B

339 m/s

C

330 m/s

D

300 m/s

Step-by-Step Solution

The velocity of sound is given by v=2f(L2L1)v = 2f(L_2 - L_1). Given f=320 Hzf = 320 \text{ Hz}, L1=20 cmL_1 = 20 \text{ cm}, L2=73 cmL_2 = 73 \text{ cm}. v=2×320×(7320)×102=640×53×102=339.2 ms1339 m/sv = 2 \times 320 \times (73 - 20) \times 10^{-2} = 640 \times 53 \times 10^{-2} = 339.2 \text{ ms}^{-1} \approx 339 \text{ m/s}.

Exam Context & Concepts Covered

This question aligns with the NEET general syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

generaltuningproduceresonancelengthcolumn

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