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NEET generalGeneralMedium

Question

An em wave is propagating in a medium with →\rightarrow a velocity v^\hat{v} V=ViV = V_i ==. The instantaneous oscillating electric field of this em wave is along +y+y axis. Then the direction of oscillating magnetic field of the em wave will be along

A

–y direction

B

+z direction

C

–z direction

D

–x direction

Step-by-Step Solution

Sol. E⃗×B⃗=V⃗\vec{E} \times \vec{B} = \vec{V}

(Ej^)×(B⃗)=Vi^(E\hat{j}) \times (\vec{B}) = V\hat{i}

So, B⃗=Bk^\vec{B} = B\hat{k}

Direction of propagation is along +z direction.

Exam Context & Concepts Covered

This question aligns with the NEET general syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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