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NEET generalGeneralMedium

Question

Current sensitivity of a moving coil galvanometer is 5 div/mA5 \text{ div/mA} and its voltage sensitivity (angular deflection per unit voltage applied) is 20 div/V20 \text{ div/V}. The resistance of the galvanometer is

1

250 Ω\Omega

2

25 Ω\Omega

3

40 Ω\Omega

4

500 Ω\Omega

Step-by-Step Solution

Current sensitivity IS=NBACI_S = \frac{NBA}{C}. Voltage sensitivity VS=NBACRGV_S = \frac{NBA}{CR_G}. So, resistance of galvanometer RG=ISVS=5×120×10−3=500020=250 ΩR_G = \frac{I_S}{V_S} = \frac{5 \times 1}{20 \times 10^{-3}} = \frac{5000}{20} = 250 \text{ }\Omega.

Exam Context & Concepts Covered

This question aligns with the NEET general syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

generalcurrentsensitivitymovinggalvanometervoltage

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