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NEET generalGeneralEasy

Question

In Young's double slit experiment the separation d between the slits is 2 mm, the wavelength  of the light used is 5896 Å and distance D between the screen and slits is 100 cm. It is found that the angular width of the fringes is 0.20°. To increase the fringe angular width to 0.21° (with same  and D) the separation between the slits needs to be changed to

A

2.1mm

B

1.9mm

C

1.8mm

D

1.7mm

Step-by-Step Solution

Sol. Angular width=λd\text{Angular width} = \frac{\lambda}{d}

0.20∘=λ2 mm…(i)0.20^\circ = \frac{\lambda}{2 \text{ mm}} \quad \dots(i)

0.21∘=λd…(ii)0.21^\circ = \frac{\lambda}{d} \quad \dots(ii)

Dividing we get, 0.200.21=d2 mm\frac{0.20}{0.21} = \frac{d}{2 \text{ mm}}

∴d=1.9 mm\therefore d = 1.9 \text{ mm}

Exam Context & Concepts Covered

This question aligns with the NEET general syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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