The compound $C_7H_8$ undergoes the following reactions: $C_7H_8 \xrightarrow{3Cl_2/\Delta} A \xrightarrow{Br_

Question

The compound $C_7H_8$ undergoes the following reactions: $C_7H_8 \xrightarrow{3Cl_2/\Delta} A \xrightarrow{Br_2/Fe} B \xrightarrow{Zn/HCl} C$. The product 'C' is

Accepted Answer

Toluene ($C_7H_8$) reacts with $3Cl_2/\Delta$ to form benzotrichloride. Then $Br_2/Fe$ performs electrophilic substitution at the meta position due to the deactivating $-CCl_3$ group. Finally, $Zn/HCl$ reduces $-CCl_3$ to $-CH_3$.

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