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NEET generalGeneralMedium

Question

The power radiated by a black body is PP and it radiates maximum energy at wavelength, λ0\lambda_0. If the temperature of the black body is now changed so that it radiates maximum energy 34λ0\frac{3}{4} \lambda_0 , the power radiated by it becomes nPnP. The value of nn is

A

256/81256/81

B

43\frac{4}{3}

C

34\frac{3}{4}

D

81256\frac{81}{256}

Step-by-Step Solution

λmaxT=constant(Wien’s law)\lambda_{\text{max}} T = \text{constant} \quad \text{(Wien's law)}

So, λmax1T1=λmax2T2\textbf{So, } \lambda_{\text{max}_1} T_1 = \lambda_{\text{max}_2} T_2

λ0T=3λ04T\Rightarrow \lambda_0 T = \frac{3\lambda_0}{4} T'

T=43T\Rightarrow T' = \frac{4}{3}T

So, P2P1=(TT)4=(43)4=25681\textbf{So, } \frac{P_2}{P_1} = \left(\frac{T'}{T}\right)^4 = \left(\frac{4}{3}\right)^4 = \frac{256}{81}

Exam Context & Concepts Covered

This question aligns with the NEET general syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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