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NEET generalGeneralMedium

Question

The refractive index of the material of a prism is μ=2\mu = \sqrt{2} and the angle of the prism is A=30∘A = 30^\circ. One of the two refracting surfaces of the prism is made a mirror inwards, by silver coating. A beam of monochromatic light entering the prism from the other face will retrace its path (after reflection from the silvered surface) if its angle of incidence on the prism is ii.

A

30 Degree

B

45 Degree

C

60 Degree

D

Zero

Step-by-Step Solution

sin⁡isin⁡30∘=21\frac{\sin i}{\sin 30^\circ} = \frac{\sqrt{2}}{1}

⇒sin⁡i=2×12\Rightarrow \sin i = \sqrt{2} \times \frac{1}{2}

sin⁡i=12 i.e. i=45∘\sin i = \frac{1}{\sqrt{2}} \text{ i.e. } i = 45^\circ

Exam Context & Concepts Covered

This question aligns with the NEET general syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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