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NEET PHYSICSNUCLEIEasy

Question

A nucleus of mass number 189 splits into two nuclei having mass numbers 125 and 64. The ratio of the radius of two daughter nuclei respectively is:

A

25:16:00

B

1:1

C

4:5

D

5:4

Step-by-Step Solution

  1. Identify the Formula: The radius (RR) of a nucleus is directly proportional to the cube root of its mass number (AA). The relationship is given by R=R0A1/3R = R_0 A^{1/3}, where R0R_0 is a constant (1.1×10151.1 \times 10^{-15} m) .
  2. Identify Given Values:
  • Mass number of first daughter nucleus (A1A_1) = 125.
  • Mass number of second daughter nucleus (A2A_2) = 64.
  1. Calculate the Ratio:
  • Ratio R1R2=R0(A1)1/3R0(A2)1/3=(A1A2)1/3\frac{R_1}{R_2} = \frac{R_0 (A_1)^{1/3}}{R_0 (A_2)^{1/3}} = \left(\frac{A_1}{A_2}\right)^{1/3}.
  • R1R2=(12564)1/3\frac{R_1}{R_2} = \left(\frac{125}{64}\right)^{1/3}.
  1. Solve the Cube Roots:
  • 125=5\sqrt{125} = 5.
  • 64=4\sqrt{64} = 4.
  • Therefore, R1R2=54\frac{R_1}{R_2} = \frac{5}{4}.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from NUCLEI. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSNUCLEInucleusnumbersplitsnucleihaving

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