back to directory
NEET PHYSICSNUCLEIEasy

Question

The energy equivalent of 0.5 g of a substance is:

A

4.5 × 10^{13} J

B

1.5 × 10^{13} J

C

0.5 × 10^{13} J

D

4.5 × 10^{16} J

Step-by-Step Solution

  1. Formula: Einstein's mass-energy equivalence relation is given by: E=mc2E = mc^2 where EE is energy, mm is mass, and cc is the speed of light in vacuum (3×108 m/s3 \times 10^8 \text{ m/s}).
  2. Unit Conversion: The mass must be in SI units (kilograms). Given mass m=0.5 gm = 0.5 \text{ g}. m=0.5×103 kg=5×104 kgm = 0.5 \times 10^{-3} \text{ kg} = 5 \times 10^{-4} \text{ kg}
  3. Calculation: Substitute the values into the formula: E=(0.5×103 kg)×(3×108 m/s)2E = (0.5 \times 10^{-3} \text{ kg}) \times (3 \times 10^8 \text{ m/s})^2 E=(0.5×103)×(9×1016)E = (0.5 \times 10^{-3}) \times (9 \times 10^{16}) E=4.5×1013 JE = 4.5 \times 10^{13} \text{ J}
  4. Conclusion: The energy equivalent is 4.5×10134.5 \times 10^{13} Joules.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from NUCLEI. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSNUCLEIenergyequivalentsubstance

More NUCLEI Questions

View all

In the nuclear reaction $X(n, \alpha){}_{3}^{7}\mathrm{Li}$, the term $X$ will be:

A.${}_{5}^{10}\mathrm{B}$
B.${}_{5}^{9}\mathrm{B}$
C.${}_{5}^{11}\mathrm{B}$
D.${}_{2}^{4}\mathrm{He}$
EasySolve

The half-life of a radioactive sample undergoing $\alpha$-decay is $1.4 \times 10^{17}\text{ s}$. If the number of nuclei in the sample is $2.0 \times 10^{21}$, the activity of the sample is nearly equal to:

A.$10^4\text{ Bq}$
B.$10^5\text{ Bq}$
C.$10^6\text{ Bq}$
D.$10^3\text{ Bq}$
MediumSolve

If the nuclear radius of $^{27}\text{Al}$ is 3.6 Fermi, the approximate nuclear radius of $^{64}\text{Cu}$ in Fermi is:

A.2.4
B.1.2
C.4.8
D.3.6
MediumSolve

The half-life of a radioactive substance is 30 minutes. The time (in minute) taken between 40% decay and 85% decay of the same radioactive substance is:

A.15
B.30
C.45
D.60
MediumSolve

The fraction of the original number of radioactive atoms that disintegrates (decays) during the average lifetime of a radioactive substance will be:

A.1/e
B.1/(1+e)
C.(e-1)/(e+1)
D.(e-1)/e
MediumSolve

A nucleus of mass number 189 splits into two nuclei having mass numbers 125 and 64. The ratio of the radius of two daughter nuclei respectively is:

A.25:16:00
B.1:1
C.4:5
D.5:4
EasySolve

In the nuclear emission stated above: ${}_{82}^{290}X \xrightarrow{\alpha} Y \xrightarrow{e^+} Z \xrightarrow{\beta^-} P \xrightarrow{e^-} Q$, the mass number and atomic number of the product Q respectively, are:

A.286, 80
B.288, 82
C.286, 81
D.280, 81
MediumSolve

After two hours, one-sixteenth of the starting amount of a certain radioactive isotope remained undecayed. The half life of the isotope is

A.15 minutes
B.30 minutes
C.45 minutes
D.1 hour
EasySolve

This neet physics practice question is part of the TopperSquare free question bank. TopperSquare offers 15,000+ chapter-wise NEET MCQs across Physics, Chemistry, and Biology with detailed step-by-step explanations, full mock tests, NEET PYQs (2010–2024), and an AI-powered performance analytics dashboard. browse all neet practice questions → · practice physics sets →