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NEET PHYSICSNUCLEIEasy

Question

In the nuclear reaction X(n,α)37LiX(n, \alpha){}_{3}^{7}\mathrm{Li}, the term XX will be:

A

510B{}_{5}^{10}\mathrm{B}

B

59B{}_{5}^{9}\mathrm{B}

C

511B{}_{5}^{11}\mathrm{B}

D

24He{}_{2}^{4}\mathrm{He}

Step-by-Step Solution

  1. Interpret Reaction Notation: The notation X(n,α)YX(n, \alpha)Y represents a nuclear reaction where a target nucleus XX absorbs a neutron (nn) and emits an \alpha particle (α\alpha) to form the product nucleus YY. The reaction is written as: X+01n37Li+24HeX + {}_{0}^{1}n \rightarrow {}_{3}^{7}\mathrm{Li} + {}_{2}^{4}\mathrm{He} .
  2. Apply Conservation Laws: In any nuclear reaction, both the mass number (AA, sum of protons and neutrons) and the atomic number (ZZ, number of protons) must be conserved .
  • Conservation of Mass Number (AA): AX+1=7+4    AX=10A_X + 1 = 7 + 4 \implies A_X = 10.
  • Conservation of Atomic Number (ZZ): ZX+0=3+2    ZX=5Z_X + 0 = 3 + 2 \implies Z_X = 5.
  1. Identify Element: The element with atomic number Z=5Z=5 is Boron (B). Therefore, the unknown term XX is the isotope Boron-10 (510B{}_{5}^{10}\mathrm{B}).

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from NUCLEI. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSNUCLEInuclearreactionalphamathrmli

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