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NEET PHYSICSMOTION IN A PLANEMedium

Question

A particle moving in a circle of radius RR with a uniform speed takes a time TT to complete one revolution. If this particle were projected with the same speed at an angle θ\theta to the horizontal, the maximum height attained by it equals 4R4R. The angle of projection, θ\theta is then given by:

A

θ=sin1(π2RgT2)1/2\theta=\sin^{-1}\left(\frac{\pi^2R}{gT^2}\right)^{1/2}

B

θ=sin1(2gT2π2R)1/2\theta=\sin^{-1}\left(\frac{2gT^2}{\pi^2R}\right)^{1/2}

C

θ=cos1(gT2π2R)1/2\theta=\cos^{-1}\left(\frac{gT^2}{\pi^2R}\right)^{1/2}

D

θ=cos1(π2RgT2)1/2\theta=\cos^{-1}\left(\frac{\pi^2R}{gT^2}\right)^{1/2}

Step-by-Step Solution

  1. Analyze Circular Motion: The particle moves in a circle of radius RR with uniform speed vv and time period TT. The speed is distance divided by time: v=2πRTv = \frac{2\pi R}{T}
  2. Analyze Projectile Motion: The particle is projected with this same speed vv at an angle θ\theta. The maximum height HH attained in projectile motion is given by: H=v2sin2θ2gH = \frac{v^2 \sin^2 \theta}{2g}
  3. Apply Given Condition: We are given that the maximum height equals 4R4R. So, H=4RH = 4R. Substituting the expression for HH: 4R=v2sin2θ2g4R = \frac{v^2 \sin^2 \theta}{2g}
  4. Substitute and Solve: Substitute the expression for vv derived in step 1 into the equation: 4R=(2πRT)2sin2θ2g4R = \frac{\left(\frac{2\pi R}{T}\right)^2 \sin^2 \theta}{2g} 4R=4π2R2T2sin2θ2g4R = \frac{\frac{4\pi^2 R^2}{T^2} \sin^2 \theta}{2g} 4R=2π2R2sin2θgT24R = \frac{2\pi^2 R^2 \sin^2 \theta}{g T^2} Rearranging to solve for sin2θ\sin^2 \theta: sin2θ=4RgT22π2R2\sin^2 \theta = \frac{4R \cdot g T^2}{2\pi^2 R^2} sin2θ=2gT2π2R\sin^2 \theta = \frac{2g T^2}{\pi^2 R} Taking the square root: sinθ=(2gT2π2R)1/2\sin \theta = \left(\frac{2g T^2}{\pi^2 R}\right)^{1/2} θ=sin1[(2gT2π2R)1/2]\theta = \sin^{-1}\left[\left(\frac{2g T^2}{\pi^2 R}\right)^{1/2}\right]

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A PLANE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A PLANEparticlemovingcircleradiusuniform

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