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NEET PHYSICSMOTION IN A STRAIGHT LINEMedium

Question

A small block slides down on a smooth inclined plane starting from rest at time t=0t=0. Let SnS_n be the distance traveled by the block in the interval t=n1t=n-1 to t=nt=n. Then the ratio SnSn+1\frac{S_n}{S_{n+1}} is:

A

\frac{2n+1}{2n-1}

B

\frac{2n}{2n-1}

C

\frac{2n-1}{2n}

D

\frac{2n-1}{2n+1}

Step-by-Step Solution

  1. Identify the Formula: The distance traveled by a body undergoing uniformly accelerated motion in the nn-th second (interval from t=n1t = n-1 to t=nt = n) is given by the formula: Sn=u+a2(2n1)S_n = u + \frac{a}{2}(2n - 1) where uu is the initial velocity and aa is the acceleration.
  2. Apply Conditions: The block starts from rest, so u=0u = 0. The acceleration aa is constant (gsinθg \sin \theta on an incline). Thus: Sn=a2(2n1)S_n = \frac{a}{2}(2n - 1)
  3. Calculate for (n+1)-th Interval: For the next interval (t=nt = n to t=n+1t = n+1), we substitute nn with (n+1)(n+1): Sn+1=a2[2(n+1)1]=a2(2n+21)=a2(2n+1)S_{n+1} = \frac{a}{2}[2(n + 1) - 1] = \frac{a}{2}(2n + 2 - 1) = \frac{a}{2}(2n + 1)
  4. Calculate Ratio: SnSn+1=a2(2n1)a2(2n+1)=2n12n+1\frac{S_n}{S_{n+1}} = \frac{\frac{a}{2}(2n - 1)}{\frac{a}{2}(2n + 1)} = \frac{2n - 1}{2n + 1}
  5. Context: This is a generalization of Galileo's law of odd numbers found in NCERT .

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A STRAIGHT LINE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A STRAIGHT LINEslidessmoothinclinedstartingdistance

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