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Question

A vertical spring with a force constant kk is fixed on a table. A ball of mass mm at a height hh above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance dd. The net work done in the process is:

A

mg(h+d)+12kd2mg(h+d) + \frac{1}{2}kd^2

B

mg(h+d)12kd2mg(h+d) - \frac{1}{2}kd^2

C

mg(hd)12kd2mg(h-d) - \frac{1}{2}kd^2

D

mg(hd)+12kd2mg(h-d) + \frac{1}{2}kd^2

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NEET PHYSICS: "A vertical spring with a force constant $k$ is fixed on a table. A ball of mass $m$ at a height $h$ above the free upper..." — Solved MCQ | TopperSquare