An inductor of inductance 2 mH is connected to a 220 V, 50 Hz AC source. Let the inductive reactance in the ci

Question

An inductor of inductance 2 mH is connected to a 220 V, 50 Hz AC source. Let the inductive reactance in the circuit be $X_1$. If a 220 V DC source replaces the AC source in the circuit, then the inductive reactance in the circuit is $X_2$. $X_1$ and $X_2$, respectively, are:

Accepted Answer

According to the sources, inductive reactance ($X_L$) is given by the formula $X_L = \omega L = 2\pi f L$ . For the AC source, with $f = 50$ Hz and $L = 2$ mH ($2 	imes 10^{-3}$ H), the reactance $X_1 = 2 	imes \pi 	imes 50 	imes 2 	imes 10^{-3} = 0.2\pi \approx 0.628 \ \Omega$. For a DC source, the frequency ($f$) is zero, resulting in an inductive reactance $X_2 = 2\pi(0)L = 0$ (zero) .

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