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NEET PHYSICSALTERNATING CURRENTEasy

Question

A standard filament lamp consumes 100 W when connected to a 200 V AC mains supply. The peak current through the bulb will be:

A

0.707 A

B

1 A

C

1.414 A

D

2 A

Step-by-Step Solution

To find the peak current, we first calculate the RMS current (II). According to the sources, the power consumed by a resistive element like a filament lamp is P=VIP = V I, where VV and II are RMS values . Thus, I=P/V=100 W/200 V=0.5I = P / V = 100 \text{ W} / 200 \text{ V} = 0.5 A. The relationship between the peak current (imi_m) and the RMS current (II) is im=I2i_m = I\sqrt{2} . Substituting the values, im=0.5×1.414=0.707i_m = 0.5 \times 1.414 = 0.707 A.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ALTERNATING CURRENT. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSALTERNATING CURRENTstandardfilamentconsumesconnectedsupply

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