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NEET PHYSICSALTERNATING CURRENTMedium

Question

The net impedance of the circuit (as shown in the figure) will be:

A

25 Ω\Omega

B

102 Ω10\sqrt{2} \ \Omega

C

15 Ω\Omega

D

55 Ω5\sqrt{5} \ \Omega

Step-by-Step Solution

In a series LCR circuit, the net impedance (ZZ) is determined by the resistance (RR), inductive reactance (XLX_L), and capacitive reactance (XCX_C) using the phasor relationship: Z=R2+(XL−XC)2Z = \sqrt{R^2 + (X_L - X_C)^2}. For this specific problem from NEET 2023, the circuit parameters are R=10 ΩR = 10 \ \Omega, XL=10 ΩX_L = 10 \ \Omega, and XC=5 ΩX_C = 5 \ \Omega. Substituting these into the formula gives Z=102+(10−5)2=100+25=125=55 ΩZ = \sqrt{10^2 + (10 - 5)^2} = \sqrt{100 + 25} = \sqrt{125} = 5\sqrt{5} \ \Omega.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ALTERNATING CURRENT. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSALTERNATING CURRENTimpedancecircuitfigure

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