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NEET PHYSICSOscillationsEasy

Question

During simple harmonic motion of a body, the energy at the extreme position is:

A

both kinetic and potential

B

is always zero

C

purely kinetic

D

purely potential

Step-by-Step Solution

  1. Velocity at Extreme Position: In Simple Harmonic Motion (SHM), the particle oscillates between two extreme positions (±A±A) relative to a mean position (x=0x=0). At the extreme positions, the particle comes to a momentary rest, meaning its velocity (vv) is zero.
  2. Kinetic Energy: Since Kinetic Energy K=12mv2K = \frac{1}{2}mv^2, and v=0v=0 at the extremes, the kinetic energy is zero.
  3. Potential Energy: The displacement (xx) is maximum (x=±Ax = ±A) at the extreme positions. The Potential Energy (UU) is given by U=12kx2U = \frac{1}{2}kx^2. Therefore, potential energy is maximum at the extremes (Umax=12kA2U_{max} = \frac{1}{2}kA^2).
  4. Conservation of Energy: The Total Energy (EE) in SHM is the sum of kinetic and potential energies (E=K+UE = K + U). Since K=0K=0 at the extremes, the total energy is equal to the potential energy (E=UmaxE = U_{max}). Thus, the energy is purely potential .

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Oscillations. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSOscillationsduringsimpleharmonicmotionenergy

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