In the diagram shown, the normal reaction force between $2 ext{ kg}$ and $1 ext{ kg}$ blocks is: (Consider

Question

In the diagram shown, the normal reaction force between $2 	ext{ kg}$ and $1 	ext{ kg}$ blocks is: (Consider the surface to be smooth and $g=10 	ext{ m/s}^2$)

Accepted Answer

1. **Identify the System:** The problem involves two blocks (likely $m_1 = 2 	ext{ kg}$ and $m_2 = 1 	ext{ kg}$ based on the typo '222' and '111') in contact on a smooth horizontal surface. The 'normal reaction force between the blocks' is the contact force ($N$) that accelerates the second block.
2. **Theoretical Setup:** According to Newton's Second Law, if an external force $F$ is applied to $m_1$, the common acceleration $a$ is:
   $$ a = \frac{F}{m_1 + m_2} $$
   The contact force $N$ acting on $m_2$ is:
   $$ N = m_2 a = \frac{m_2 F}{m_1 + m_2} $$
3. **Data Analysis:** The provided text is missing the value of the external force $F$. However, working backward from the probable answer ($25 	ext{ N}$) and the masses ($2 	ext{ kg}, 1 	ext{ kg}$), if we assume the force is applied on the $2 	ext{ kg}$ block:
   $$ 25 = \frac{1 	imes F}{2 + 1} \Rightarrow F = 75 	ext{ N} $$
   Without the explicit mention of the force $F=75 	ext{ N}$ in the input text, the question is technically incomplete, but the physics principle relies on Newton's Laws found in the NCERT source.
   (Reference: NCERT Class 11, Physics Part I, Chapter 5: Laws of Motion, Section 5.11 'Solving Problems in Mechanics' discusses free-body diagrams and contact forces).

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