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NEET PHYSICSMOTION IN A PLANEMedium

Question

In the given figure, a=15 m/s2a=15 \text{ m/s}^2 represents the total acceleration of a particle moving in the clockwise direction in a circle of radius R=2.5 mR=2.5 \text{ m} at a given instant of time. The speed of the particle is:

A

4.5 m/s

B

5.0 m/s

C

5.7 m/s

D

6.2 m/s

Step-by-Step Solution

  1. Centripetal Acceleration Component: The particle moves in a circle, so it possesses centripetal acceleration (aca_c) directed towards the center. The given total acceleration aa has a radial component (aca_c) and a tangential component (ata_t). Based on the standard representation of this specific problem (NEET 2016), the total acceleration vector makes an angle of 3030^{\circ} with the radius vector.
  2. Formula: The radial component is ac=acosθa_c = a \cos \theta.
  3. Speed Relationship: Centripetal acceleration is defined as ac=v2Ra_c = \frac{v^2}{R} .
  4. Calculation: v2R=acos30\frac{v^2}{R} = a \cos 30^{\circ} Substituting given values (a=15,R=2.5a=15, R=2.5): v22.5=15×32\frac{v^2}{2.5} = 15 \times \frac{\sqrt{3}}{2} v2=2.5×15×0.86632.475v^2 = 2.5 \times 15 \times 0.866 \approx 32.475 v=32.4755.7 m/sv = \sqrt{32.475} \approx 5.7 \text{ m/s}

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A PLANE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A PLANEfigurerepresentsaccelerationparticlemoving

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