Question
Power dissipated in an L-C-R series circuit connected to an AC source of emf ε is
ε²R / [R² + (L\omega - 1/C\omega )²]
ε²√[R² + (L\omega - 1/C\omega )²] / R
ε²[R² + (L\omega - 1/C\omega )²] / R
ε²R / √[R² + (L\omega - 1/C\omega )²]
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