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NEET PHYSICSALTERNATING CURRENTMedium

Question

Power dissipated in an L-C-R series circuit connected to an AC source of emf ε is

A

ε²R / [R² + (L\omega - 1/C\omega )²]

B

ε²√[R² + (L\omega - 1/C\omega )²] / R

C

ε²[R² + (L\omega - 1/C\omega )²] / R

D

ε²R / √[R² + (L\omega - 1/C\omega )²]

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NEET PHYSICS: "Power dissipated in an L-C-R series circuit connected to an AC source of emf ε is..." — Solved MCQ | TopperSquare