Question
Rain is falling vertically downward with a speed of . The wind starts blowing after some time with a speed of in the east to the west direction. The direction in which a boy standing at the place should hold his umbrella is:
with respect to rain
with respect to wind
with respect to rain
with respect to wind
The problem asks for the direction to hold the umbrella to protect against rain affected by wind. This is a problem of finding the direction of the resultant velocity of the rain and wind.
Identify Velocity Vectors: Velocity of rain, (acting vertically downward) . Velocity of wind, (acting horizontally from east to west) .
Determine Resultant Direction: The effective velocity of the rain relative to the stationary boy is the vector sum (resultant) of the rain's velocity and the wind's velocity: . The umbrella must be held along the line of this resultant velocity.
Calculate the Angle (): Let be the angle the resultant makes with the vertical (the original direction of the rain). From the vector diagram (parallelogram law): Substituting the given values:
Since the vertical direction corresponds to the initial direction of the rain, the angle is with respect to the rain .
This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A PLANE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.
More MOTION IN A PLANE Questions
An object is thrown along a direction inclined at an angle of $45^\circ$ with the horizontal direction. The horizontal range of the particle is equal to:
A particle moves so that its position vector is given by $\vec{r} = \cos(\omega t)\hat{x} + \sin(\omega t)\hat{y}$, where $\omega$ is a constant. Which of the following is true?
For a projectile projected at angles $(45^{\circ}-\theta)$ and $(45^{\circ}+\theta)$, the horizontal ranges described by the projectile are in the ratio of:
A body is moving with velocity $30 \text{ m/s}$ towards east. After $10 \text{ s}$ its velocity becomes $40 \text{ m/s}$ towards north. The average acceleration of the body is:
A ball is projected with kinetic energy $E$ at an angle of $45^\circ$ to the horizontal. At the highest point during its flight, its kinetic energy will be:
Two particles $A$ and $B$, move with constant velocities $\vec{v}_1$ and $\vec{v}_2$ respectively. At the initial moment, their position vectors are $\vec{r}_1$ and $\vec{r}_2$ respectively. The condition for particles $A$ and $B$ for their collision will be:
A particle starting from the origin $(0,0)$ moves in a straight line in the $(x,y)$ plane. Its coordinates at a later time are $(\sqrt{3}, 3)$. The path of the particle makes an angle of __________ with the $x$-axis:
If a particle moves in a circle describing equal angles in equal times, its velocity vector:
Why 32,000+ students choose TopperSquare
15,000+ Chapter MCQs
Physics, Chemistry, Biology — chapter-wise, topic-wise practice
AI Performance Analytics
Know your weak topics. Get a personalised study plan.
Full NEET Mock Tests
180 questions, timed, with detailed score analysis
PYQ Sets 2010–2024
15 years of past papers with solved explanations
No credit card · 30-second signup · Free forever plan included
This neet physics practice question is part of the TopperSquare free question bank. TopperSquare offers 15,000+ chapter-wise NEET MCQs across Physics, Chemistry, and Biology with detailed step-by-step explanations, full mock tests, NEET PYQs (2010–2024), and an AI-powered performance analytics dashboard. browse all neet practice questions → · practice physics sets →
Sign in to save your score, view detailed analytics, and bookmark tough questions for revision.
Sign In / Join FreeChapter-wise practice sets
Identify weak areas instantly
Step-by-step logic for every question