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NEET PHYSICSOscillationsMedium

Question

The displacement of a particle along the x-axis is given by x=asin2ωtx = a \sin^2 \omega t. The motion of the particle corresponds to:

A

simple harmonic motion of frequency ω/π\omega/\pi

B

simple harmonic motion of frequency 3ω/2π3\omega/2\pi

C

non-simple harmonic motion

D

simple harmonic motion of frequency ω/2π\omega/2\pi

Step-by-Step Solution

To identify the nature of the motion and its frequency, we simplify the given displacement equation using the trigonometric identity sin2θ=1cos2θ2\sin^2 \theta = \frac{1 - \cos 2\theta}{2}.

Given: x=asin2ωtx = a \sin^2 \omega t Substituting the identity: x=a(1cos2ωt2)x = a \left( \frac{1 - \cos 2\omega t}{2} \right) x=a2a2cos(2ωt)x = \frac{a}{2} - \frac{a}{2} \cos(2\omega t)

This equation describes a Simple Harmonic Motion (SHM) where the particle oscillates about a shifted equilibrium position (x0=a/2x_0 = a/2). The oscillating term is cos(2ωt)\cos(2\omega t).

The angular frequency of this motion is the coefficient of tt in the cosine term: ω=2ω\omega' = 2\omega

The relationship between frequency (ff or ν\nu) and angular frequency is given by f=ω2πf = \frac{\omega'}{2\pi} . Substituting ω\omega': f=2ω2π=ωπf = \frac{2\omega}{2\pi} = \frac{\omega}{\pi}

Therefore, the motion is simple harmonic with a frequency of ω/π\omega/\pi.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Oscillations. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSOscillationsdisplacementparticlemotionparticlecorresponds

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