Question
The ground state energy of hydrogen atom is 13.6 eV. The energy needed to ionise the atom from its second excited state is:
1.51 eV
3.4 eV
13.6 eV
12.1 eV
The energy of an electron in the -th orbit of a hydrogen atom is given by eV . The ground state corresponds to . The 'second excited state' corresponds to the principal quantum number (as is the first excited state).
Calculating the energy of the electron in the orbit: .
The ionization energy is the energy required to remove the electron from this state to infinity (where energy is 0). Ionization Energy = .
This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ATOMS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.
More ATOMS Questions
The Bohr model for the spectra of a H-atom: (a) will not apply to hydrogen in the molecular form. (b) will not be applicable as it is for a He-atom. (c) is valid only at room temperature. (d) predicts continuous as well as discrete spectral lines. Choose the correct option:
Let En = -(me^4)/(8ε_0^2 n^2 h^2) be the energy of the nth level of H-atom. If all the H-atoms are in the ground state and radiation of frequency (E2 - E1)/h falls on it, then: (a) it will not be absorbed at all. (b) some of the atoms will move to the first excited state. (c) all atoms will be excited to the n=2 state. (d) no atoms will make a transition to the n=3 state. Choose the correct option:
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In the Bohr's model of a hydrogen atom, the centripetal force is furnished by the Coulomb attraction between the proton and the electron. If a₀ is the radius of the ground state orbit, m is the mass and e is the charge on the electron, ε₀ is the vacuum permittivity, the speed of the electron is:
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