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NEET PHYSICSATOMSEasy

Question

The ionisation energy of hydrogen atom is 13.6 eV, the ionisation energy of helium atom would be:

A

13.6 eV

B

27.2 eV

C

6.8 eV

D

54.4 eV

Step-by-Step Solution

According to the Bohr model, the energy of an electron in a hydrogen-like species (single electron system) is proportional to the square of the atomic number (ZZ). The ionization energy (IE) is given by IE=13.6×Z2n2IE = 13.6 \times \frac{Z^2}{n^2} eV. For the ground state (n=1n=1):

  1. For Hydrogen (Z=1Z=1): IE=13.6×12=13.6IE = 13.6 \times 1^2 = 13.6 eV.
  2. For Helium ion (He+He^+, Z=2Z=2): IE=13.6×22=13.6×4=54.4IE = 13.6 \times 2^2 = 13.6 \times 4 = 54.4 eV. (Note: While the question says 'helium atom', the answer 54.4 eV corresponds to the singly ionized helium ion He+He^+, which is a hydrogen-like species applicable to Bohr's theory. The ionization energy of neutral Helium is \approx 24.6 eV).

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ATOMS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSATOMSionisationenergyhydrogenionisationenergy

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