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NEET PHYSICSMOTION IN A PLANEEasy

Question

Two particles AA and BB are moving in a uniform circular motion in concentric circles of radii rAr_A and rBr_B with speeds vAv_A and vBv_B respectively. Their time periods of rotation are the same. The ratio of the angular speed of AA to that of BB will be:

A

1 : 1

B

rA:rBr_A : r_B

C

vA:vBv_A : v_B

D

rB:rAr_B : r_A

Step-by-Step Solution

  1. Definition of Angular Speed: The angular speed ω\omega of a particle performing uniform circular motion is related to its time period TT (time for one complete revolution) by the formula ω=2πT\omega = \frac{2\pi}{T} .
  2. Analyze the Condition: The problem states that the time periods of rotation for both particles are the same, i.e., TA=TBT_A = T_B.
  3. Calculate Ratio: ωA=2πTA\omega_A = \frac{2\pi}{T_A} ωB=2πTB\omega_B = \frac{2\pi}{T_B} Since TA=TBT_A = T_B, it implies that ωA=ωB\omega_A = \omega_B.
  4. Conclusion: The ratio of their angular speeds is ωA:ωB=1:1\omega_A : \omega_B = 1 : 1. The radii and linear speeds are not needed to determine this specific ratio given the constant time period condition.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A PLANE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A PLANEparticlesmovinguniformcircularmotion

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