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NEET PHYSICSMOTION IN A PLANEEasy

Question

Two racing cars of masses m1m_1 and m2m_2 are moving in circles of radii r1r_1 and r2r_2 respectively. Their speeds are such that each makes a complete circle in the same duration of time tt. The ratio of the angular speed of the first to the second car is:

A

m1:m2m_1:m_2

B

r1:r2r_1:r_2

C

1:11:1

D

m1r1:m2r2m_1r_1:m_2r_2

Step-by-Step Solution

In uniform circular motion, the angular speed ω\omega is defined as the angle covered per unit time. For a complete revolution (angle 2π2\pi), if the time taken is the time period TT, then the angular speed is given by ω=2πT\omega = \frac{2\pi}{T} .

Given that both cars complete the circle in the same duration of time tt, their time periods are equal (T1=T2=tT_1 = T_2 = t). Therefore, their angular speeds are: ω1=2πt\omega_1 = \frac{2\pi}{t} ω2=2πt\omega_2 = \frac{2\pi}{t}

The ratio is ω1:ω2=1:1\omega_1 : \omega_2 = 1 : 1. The angular speed is independent of the mass and radius when the time period is fixed.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A PLANE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A PLANEracingmassesmovingcirclesrespectively

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