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NEET PHYSICSOscillationsEasy

Question

Two simple harmonic motions of angular frequencies 100100 and 1000 rad s11000 \text{ rad s}^{-1} have the same displacement amplitude. The ratio of their maximum acceleration is:

A

1:101: 10

B

1:1021: 10^2

C

1:1031: 10^3

D

1:1041: 10^4

Step-by-Step Solution

  1. Identify Maximum Acceleration Formula: In Simple Harmonic Motion, the magnitude of maximum acceleration of a particle is given by amax=ω2Aa_{max} = \omega^2 A, where ω\omega is the angular frequency and AA is the amplitude .
  2. Set up Ratio: Let the two SHMs have angular frequencies ω1=100 rad s1\omega_1 = 100 \text{ rad s}^{-1} and ω2=1000 rad s1\omega_2 = 1000 \text{ rad s}^{-1}. They have the same amplitude, so A1=A2=AA_1 = A_2 = A.
  3. Calculate Ratio: Ratio=amax1amax2=ω12A1ω22A2\text{Ratio} = \frac{a_{max1}}{a_{max2}} = \frac{\omega_1^2 A_1}{\omega_2^2 A_2} Since A1=A2A_1 = A_2, this simplifies to: Ratio=(ω1ω2)2=(1001000)2\text{Ratio} = \left(\frac{\omega_1}{\omega_2}\right)^2 = \left(\frac{100}{1000}\right)^2 Ratio=(110)2=1100=1:102\text{Ratio} = \left(\frac{1}{10}\right)^2 = \frac{1}{100} = 1: 10^2

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Oscillations. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSOscillationssimpleharmonicmotionsangularfrequencies

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