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NEET CHEMISTRYStructure of AtomMedium

Question

4d, 5p, 5f and 6p orbitals are arranged in the order of decreasing energy. The correct option is:

A

5f > 6p > 4d > 5p

B

5f > 6p > 5p > 4d

C

6p > 5f > 5p > 4d

D

6p > 5f > 4d > 5p

Step-by-Step Solution

According to the Aufbau Principle, the energy of atomic orbitals is determined by the (n+l)(n + l) rule:

  1. Lower (n+l)(n + l) = Lower Energy.
  2. If (n+l)(n + l) is equal, the orbital with the lower nn value has lower energy.

Analysis of given orbitals:

  • 5f: n=5,l=3  ⟹  (n+l)=8n=5, l=3 \implies (n+l) = 8
  • 6p: n=6,l=1  ⟹  (n+l)=7n=6, l=1 \implies (n+l) = 7
  • 5p: n=5,l=1  ⟹  (n+l)=6n=5, l=1 \implies (n+l) = 6
  • 4d: n=4,l=2  ⟹  (n+l)=6n=4, l=2 \implies (n+l) = 6

Ordering:

  • Highest Energy: 5f5f (sum = 8)
  • Second: 6p6p (sum = 7)
  • Tie-break (5p vs 4d): Both have a sum of 6. The orbital with the higher nn (5p) has higher energy.
  • 5p>4d5p > 4d

Final Decreasing Order: 5f>6p>5p>4d5f > 6p > 5p > 4d

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Structure of Atom. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYStructure of Atomorbitalsarrangeddecreasingenergycorrect

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