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NEET CHEMISTRYStructure of AtomEasy

Question

A particular station of All India Radio, New Delhi, broadcasts on a frequency of 1,368 kHz1,368 \text{ kHz} (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is: [speed of light, c=3.0×108 m s1c = 3.0 \times 10^8 \text{ m s}^{-1}]

A

2192 m

B

21.92 cm

C

219.3 m

D

219.2 m

Step-by-Step Solution

The wavelength (λ\lambda), frequency (ν\nu), and speed of light (cc) are related by the equation: c=νλλ=cνc = \nu \lambda \Rightarrow \lambda = \frac{c}{\nu}

  1. Identify Given Values: Frequency (ν\nu) = 1368 kHz=1368×103 s11368 \text{ kHz} = 1368 \times 10^3 \text{ s}^{-1} (or Hz) Speed of light (cc) = 3.0×108 m s13.0 \times 10^8 \text{ m s}^{-1}

  2. Calculate Wavelength (λ\lambda): λ=3.0×108 m s11368×103 s1\lambda = \frac{3.0 \times 10^8 \text{ m s}^{-1}}{1368 \times 10^3 \text{ s}^{-1}} λ=3000×10513.68×105 m\lambda = \frac{3000 \times 10^5}{13.68 \times 10^5} \text{ m} (Adjusting powers for easier division) λ=3.0×1081.368×106 m\lambda = \frac{3.0 \times 10^8}{1.368 \times 10^6} \text{ m} λ=219.298... m\lambda = 219.298... \text{ m}

  3. Rounding: Rounding to one decimal place, λ219.3 m\lambda \approx 219.3 \text{ m}.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Structure of Atom. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYStructure of Atomparticularstationbroadcastsfrequencykilohertz

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