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NEET CHEMISTRYP Block ElementsMedium

Question

Aluminium chloride in acidified aqueous solution forms a complex 'A'. The formula of A and hybridisation state of Al in 'A' is respectively:

A

[Al(H₂O)₆]³⁺, sp³d²

B

[Al(H₂O)₄]³⁺, sp³

C

[Al(H₂O)₄]³⁺, dsp²

D

[Al(H₂O)]³⁺, d²sp³

Step-by-Step Solution

Aluminium is a Group 13 element located in the third period. Unlike the first member of the group (Boron), which has a maximum covalency of 4 (e.g., [BF₄]⁻), aluminium has vacant d-orbitals in its valence shell, allowing it to expand its coordination number beyond 4 [Source 70]. In an acidified aqueous solution, aluminium chloride dissolves to form the hexaaquaaluminium(III) ion, where the central metal ion is surrounded by six water molecules. The formula of this complex is [Al(H2O)6]3+[Al(H_2O)_6]^{3+}. To form this octahedral complex, the Al³⁺ ion (electronic configuration [Ne]) utilizes its empty 3s, 3p, and two 3d orbitals for hybridization, resulting in sp³d² hybridisation [Source 30, 70, 111].

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from P Block Elements. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYP Block Elementsaluminiumchlorideacidifiedaqueoussolution

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