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NEET CHEMISTRYP Block ElementsEasy

Question

Identify the incorrect statement:

A

Carbon has the tendency to form chains and rings with itself.

B

Silicon and Germanium are useful in semiconductor industry.

C

Boron trifluoride is a strong Lewis acid.

D

Common oxidation states of group 14 elements are +1 and +3.

Step-by-Step Solution

Let us evaluate all the statements:

  1. Carbon exhibits a strong tendency for catenation, allowing it to form long chains and rings with itself through strong covalent bonds. This statement is correct.
  2. Silicon (Si) and Germanium (Ge) are metalloids that are extensively used as semiconductors in the electronics industry. This statement is correct.
  3. Boron trifluoride (BF3BF_3) is an electron-deficient molecule with an incomplete octet on the boron atom. It readily accepts a lone pair of electrons from donors (like NH3NH_3), making it a strong Lewis acid. This statement is correct.
  4. Group 14 elements (C, Si, Ge, Sn, Pb) have a general valence shell electronic configuration of ns2np2ns^2 np^2. Thus, their common oxidation states are +2 and +4. The oxidation states of +1 and +3 are characteristic of Group 13 elements. Therefore, this statement is incorrect.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from P Block Elements. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYP Block Elementsidentifyincorrectstatement

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The number of carbon atoms per unit cell of diamond unit cell is:

A.4
B.8
C.6
D.1
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A.Sn2+ is an oxidizing agent while Pb4+ is a reducing agent.
B.Sn2+ and Pb2+ both are oxidizing agents.
C.Sn4+ is a reducing agent while Pb4+ is an oxidizing agent.
D.Sn2+ is a reducing agent while Pb4+ is an oxidizing agent.
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A.NH3
B.BF3
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A.Both diamond and graphite are used as dry lubricants.
B.Diamond and graphite have a two-dimensional network.
C.Diamond is covalent and graphite is ionic.
D.Diamond is $sp^3$ hybridised and graphite is $sp^2$ hybridized.
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A.B
B.B4C
C.B2H6
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The incorrect statement among the following is:

A.SnF4 is ionic in nature.
B.PbF4 is covalent in nature.
C.SiCl4 is easily hydrolysed.
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Which one of the following anions is present in chain structure silicates?

A.$[\text{Si}_2\text{O}_7]^{6-}$
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D.$[\text{SiO}_4]^{4-}$
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