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NEET CHEMISTRYBiomoleculesEasy

Question

D(+) glucose yields an oxime with hydroxyl amine. The structure of the oxime would be:

A

CH=NOH∣HO−C−H∣HO−C−H∣H−C−OH∣H−C−OH∣CH2OH\begin{matrix} \text{CH=NOH} \\ | \\ \text{HO}-\text{C}-\text{H} \\ | \\ \text{HO}-\text{C}-\text{H} \\ | \\ \text{H}-\text{C}-\text{OH} \\ | \\ \text{H}-\text{C}-\text{OH} \\ | \\ \text{CH}_{2}\text{OH} \end{matrix}

B

CH=NOH∣H−C−OH∣H−C−OH∣HO−C−H∣H−C−OH∣CH2OH\begin{matrix} \text{CH=NOH} \\ | \\ \text{H}-\text{C}-\text{OH} \\ | \\ \text{H}-\text{C}-\text{OH} \\ | \\ \text{HO}-\text{C}-\text{H} \\ | \\ \text{H}-\text{C}-\text{OH} \\ | \\ \text{CH}_{2}\text{OH} \end{matrix}

C

CH=NOH∣H−C−OH∣HO−C−H∣HO−C−H∣H−C−OH∣CH2OH\begin{matrix} \text{CH=NOH} \\ | \\ \text{H}-\text{C}-\text{OH} \\ | \\ \text{HO}-\text{C}-\text{H} \\ | \\ \text{HO}-\text{C}-\text{H} \\ | \\ \text{H}-\text{C}-\text{OH} \\ | \\ \text{CH}_{2}\text{OH} \end{matrix}

D

CH=NOH∣H−C−OH∣HO−C−H∣H−C−OH∣H−C−OH∣CH2OH\begin{matrix} \text{CH=NOH} \\ | \\ \text{H}-\text{C}-\text{OH} \\ | \\ \text{HO}-\text{C}-\text{H} \\ | \\ \text{H}-\text{C}-\text{OH} \\ | \\ \text{H}-\text{C}-\text{OH} \\ | \\ \text{CH}_{2}\text{OH} \end{matrix}

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NEET CHEMISTRY: "D(+) glucose yields an oxime with hydroxyl amine. The structure of the oxime would be:..." — Solved MCQ | TopperSquare