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NEET CHEMISTRYAldehydes, Ketones and Carboxylic AcidsEasy

Question

Ethylbenzene is obtained from phenyl methyl ketone by using:

A

Zn–Hg+HCl

B

LiAlH4

C

KMnO4

D

None of the above

Step-by-Step Solution

Phenyl methyl ketone is Acetophenone (C6H5COCH3C_6H_5COCH_3). The conversion of acetophenone to ethylbenzene (C6H5CH2CH3C_6H_5CH_2CH_3) involves the reduction of the carbonyl group (>C=O>C=O) to a methylene group (−CH2−-CH_2-). This specific transformation is achieved using Zinc amalgam and concentrated hydrochloric acid (Zn-Hg + HCl), a reaction known as the Clemmensen Reduction.

LiAlH4LiAlH_4 is a reducing agent that would reduce the ketone to a secondary alcohol (1-phenylethanol), not a hydrocarbon. KMnO4KMnO_4 is a strong oxidizing agent and would not reduce the carbonyl group.

  • Zn-Hg/HCl is the standard reagent for reducing aldehydes and ketones to alkanes in acidic media.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Aldehydes, Ketones and Carboxylic Acids. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYAldehydes, Ketones and Carboxylic Acidsethylbenzeneobtainedphenylmethylketone

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