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NEET CHEMISTRYP Block ElementsMedium

Question

In a Borax bead test, which compound is formed?

A

Orthoborate

B

Metaborate

C

Double oxide

D

Tetraborate

Step-by-Step Solution

When Borax (Na2B4O710H2ONa_2B_4O_7 \cdot 10H_2O) is heated, it first loses water of crystallisation and swells up. On further heating, it melts to form a clear, transparent, glassy bead composed of Sodium Metaborate (NaBO2NaBO_2) and Boric Anhydride (B2O3B_2O_3). Reaction: Na2B4O7Δ2NaBO2+B2O3Na_2B_4O_7 \xrightarrow{\Delta} 2NaBO_2 + B_2O_3 When this glassy bead is heated with a coloured metal oxide (like Cobalt oxide), the metal oxide reacts with the boric anhydride to form a characteristic coloured metaborate. Example: CoO+B2O3Co(BO2)2CoO + B_2O_3 \rightarrow Co(BO_2)_2 (Cobalt metaborate - Blue). (Note: This specific qualitative analysis test is a standard part of the chemistry curriculum for Boron compounds, though the reaction details are not explicitly found in the provided text snippets).

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from P Block Elements. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYP Block Elementscompoundformed

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