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NEET CHEMISTRYElectrochemistryEasy

Question

Limiting molar conductivity of NH4OH\text{NH}_4\text{OH} (i.e. Λm(NH4OH)\Lambda^\circ_m(\text{NH}_4\text{OH})) is equal to:

A

Λm(NH4Cl)+Λm(NaCl)Λm(NaOH)\Lambda^\circ_m(\text{NH}_4\text{Cl}) + \Lambda^\circ_m(\text{NaCl}) - \Lambda^\circ_m(\text{NaOH})

B

Λm(NaOH)+Λm(NaCl)Λm(NH4Cl)\Lambda^\circ_m(\text{NaOH}) + \Lambda^\circ_m(\text{NaCl}) - \Lambda^\circ_m(\text{NH}_4\text{Cl})

C

Λm(NH4OH)+Λm(NH4Cl)Λm(HCl)\Lambda^\circ_m(\text{NH}_4\text{OH}) + \Lambda^\circ_m(\text{NH}_4\text{Cl}) - \Lambda^\circ_m(\text{HCl})

D

Λm(NH4Cl)+Λm(NaOH)Λm(NaCl)\Lambda^\circ_m(\text{NH}_4\text{Cl}) + \Lambda^\circ_m(\text{NaOH}) - \Lambda^\circ_m(\text{NaCl})

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NEET CHEMISTRY: "Limiting molar conductivity of $\text{NH}_4\text{OH}$ (i.e. $\Lambda^\circ_m(\text{NH}_4\text{OH})$) is equal to:..." — Solved MCQ | TopperSquare