The conductivity of centimolar solution of KCl at $25^{\circ} ext{C}$ is $0.0210 ext{ ohm}^{–1} ext{ cm}^{–

Question

The conductivity of centimolar solution of KCl at $25^{\circ}	ext{C}$ is $0.0210	ext{ ohm}^{–1}	ext{ cm}^{–1}$ and the resistance of the cell containing the solution at $25^{\circ}	ext{C}$ is $60	ext{ ohm}$. The value of the cell constant is:

Accepted Answer

Given:
Conductivity ($\kappa$) = $0.0210	ext{ \Omega}^{-1}	ext{ cm}^{-1}$
Resistance ($R$) = $60	ext{ \Omega}$

The relation between cell constant ($G^*$), conductivity ($\kappa$), and resistance ($R$) is:
$	ext{Cell constant } (G^*) = 	ext{Conductivity } (\kappa) 	imes 	ext{Resistance } (R)$

Substituting the given values into the formula:
$G^* = 0.0210	ext{ \Omega}^{-1}	ext{ cm}^{-1} 	imes 60	ext{ \Omega}$
$G^* = 1.26	ext{ cm}^{-1}$

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