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NEET CHEMISTRYElectrochemistryEasy

Question

The conductivity of centimolar solution of KCl at 25C25^{\circ}\text{C} is 0.0210 ohm1 cm10.0210\text{ ohm}^{–1}\text{ cm}^{–1} and the resistance of the cell containing the solution at 25C25^{\circ}\text{C} is 60 ohm60\text{ ohm}. The value of the cell constant is:

A

3.34 cm13.34\text{ cm}^{–1}

B

1.34 cm11.34\text{ cm}^{–1}

C

3.28 cm13.28\text{ cm}^{–1}

D

1.26 cm11.26\text{ cm}^{–1}

Step-by-Step Solution

Given: Conductivity (κ\kappa) = 0.0210 \Omega1 cm10.0210\text{ \Omega}^{-1}\text{ cm}^{-1} Resistance (RR) = 60 \Omega60\text{ \Omega}

The relation between cell constant (GG^*), conductivity (κ\kappa), and resistance (RR) is: Cell constant (G)=Conductivity (κ)×Resistance (R)\text{Cell constant } (G^*) = \text{Conductivity } (\kappa) \times \text{Resistance } (R)

Substituting the given values into the formula: G=0.0210 \Omega1 cm1×60 \OmegaG^* = 0.0210\text{ \Omega}^{-1}\text{ cm}^{-1} \times 60\text{ \Omega} G=1.26 cm1G^* = 1.26\text{ cm}^{-1}

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Electrochemistry. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYElectrochemistryconductivitycentimolarsolutioncirctextcohmtext

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