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NEET CHEMISTRYAldehydes, Ketones and Carboxylic AcidsMedium

Question

The correct IUPAC name of the following compound is:

A

2-Ethylhex-3-en-4-one

B

4-Methylhex-3-en-2-one

C

4-Ethylpent-3-en-2-one

D

3-Methylhex-3-en-4-one

Step-by-Step Solution

Based on IUPAC nomenclature rules, the principal functional group must be given the lowest possible number. Here, the ketone (>C=O>C=O) group has higher priority than the carbon-carbon double bond (C=C-C=C-) [Source 153]. The longest continuous carbon chain containing both the ketone group and the double bond is selected. If the structure is CH3COCH=C(CH3)CH2CH3CH_3-CO-CH=C(CH_3)-CH_2-CH_3 (often drawn misleadingly as a 5-carbon chain with an ethyl substituent), the longest chain actually contains 6 carbons (hex). Numbering from the end closer to the carbonyl group gives the ketone at position 2, the alkene at position 3, and a methyl group substituent at position 4. Hence, the correct IUPAC name is 4-Methylhex-3-en-2-one.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Aldehydes, Ketones and Carboxylic Acids. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYAldehydes, Ketones and Carboxylic Acidscorrectfollowingcompound

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