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NEET CHEMISTRYStructure of AtomEasy

Question

The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is:

A

5, 1, 1, +1/2

B

6, 0, 0, +1/2

C

5, 0, 0, +1/2

D

5, 1, 0, +1/2

Step-by-Step Solution

To determine the quantum numbers for the valence electron of Rubidium (Rb, Z=37):

  1. Electronic Configuration: Rubidium is an alkali metal located in Group 1 and Period 5 of the periodic table. Its electronic configuration corresponds to the noble gas Krypton (Z=36) followed by one electron in the next shell.
  • Configuration: [Kr]5s1[Kr] 5s^1
  1. Identify Quantum Numbers for the 5s electron:
  • Principal Quantum Number (n): The electron is in the 5th shell, so n=5n = 5.
  • Azimuthal Quantum Number (l): The electron is in an 's' subshell. For s-orbitals, l=0l = 0.
  • Magnetic Quantum Number (m): The value of mm ranges from −l-l to +l+l. Since l=0l = 0, m=0m = 0.
  • Spin Quantum Number (s): Can be +1/2+1/2 or −1/2-1/2. The option +1/2+1/2 is standard.
  1. Conclusion: The set is 5,0,0,+1/25, 0, 0, +1/2.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Structure of Atom. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYStructure of Atomcorrectquantumnumbersvalenceelectron

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