The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is:

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To determine the quantum numbers for the valence electron of Rubidium (Rb, Z=37):

1.  **Electronic Configuration:** Rubidium is an alkali metal located in Group 1 and Period 5 of the periodic table. Its electronic configuration corresponds to the noble gas Krypton (Z=36) followed by one electron in the next shell.
    *   Configuration: $[Kr] 5s^1$

2.  **Identify Quantum Numbers for the 5s electron:**
    *   **Principal Quantum Number (n):** The electron is in the 5th shell, so $n = 5$.
    *   **Azimuthal Quantum Number (l):** The electron is in an 's' subshell. For s-orbitals, $l = 0$.
    *   **Magnetic Quantum Number (m):** The value of $m$ ranges from $-l$ to $+l$. Since $l = 0$, $m = 0$.
    *   **Spin Quantum Number (s):** Can be $+1/2$ or $-1/2$. The option $+1/2$ is standard.

3.  **Conclusion:** The set is $5, 0, 0, +1/2$.

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