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NEET CHEMISTRYAlcohols, Phenols and EthersMedium

Question

The end product in the below-mentioned reaction is: H3C-BrKCNAH3O+BLiAlH4, EtherC\text{H}_3\text{C-Br} \xrightarrow{\text{KCN}} \text{A} \xrightarrow{\text{H}_3\text{O}^+} \text{B} \xrightarrow{\text{LiAlH}_4\text{, Ether}} \text{C}

A

Acetone

B

Methane

C

Acetaldehyde

D

Ethyl alcohol

Step-by-Step Solution

Step 1: Methyl bromide (H3C-Br\text{H}_3\text{C-Br}) reacts with KCN\text{KCN} to undergo nucleophilic substitution (SN2S_N2), yielding methyl cyanide or acetonitrile (Compound A) as the major product. Step 2: Acetonitrile (CH3CN\text{CH}_3\text{CN}) on complete acidic hydrolysis (H3O+\text{H}_3\text{O}^+) gives acetic acid or ethanoic acid (Compound B). Step 3: Acetic acid (CH3COOH\text{CH}_3\text{COOH}) is reduced by the strong reducing agent lithium aluminium hydride (LiAlH4\text{LiAlH}_4) in the presence of ether to form ethyl alcohol or ethanol (Compound C). Thus, the final product C is ethyl alcohol.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Alcohols, Phenols and Ethers. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYAlcohols, Phenols and Ethersproductbelowmentionedreactiontexthtextcbrxrightarrowtextkcn

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