The name of the electrophile involved in the below reaction (Reimer-Tiemann reaction) is:

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The reaction implied is the **Reimer-Tiemann reaction**, used to prepare salicylaldehyde (2-hydroxybenzaldehyde) from phenol.

**Mechanism of Electrophile Generation:**
1.  The hydroxide ion ($OH^-$) from the alkali removes the acidic proton from chloroform ($CHCl_3$) to form the trichloromethyl carbanion ($^-CCl_3$).
    $$ CHCl_3 + OH^- \rightleftharpoons H_2O + ^-CCl_3 $$
2.  The carbanion loses a chloride ion ($Cl^-$) to form **dichlorocarbene** ($:CCl_2$).
    $$ ^-CCl_3 \rightarrow :CCl_2 + Cl^- $$

**Dichlorocarbene** contains a sextet of electrons (electron-deficient) and acts as the **electrophile** that attacks the electron-rich benzene ring of the phenoxide ion.

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