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NEET CHEMISTRYHydrocarbonsMedium

Question

The oxidation of benzene by V2_2O5_5 in the presence of air produces:

A

Benzoic anhydride

B

Maleic anhydride

C

Benzoic acid

D

Benzaldehyde

Step-by-Step Solution

  1. Stability of Benzene: The benzene ring is generally stable to strong oxidising agents like KMnO4KMnO_4 or K2Cr2O7K_2Cr_2O_7; typically, only the alkyl side chains are oxidised (e.g., Toluene to Benzoic acid).
  2. Catalytic Oxidation: However, under vigorous conditions—specifically heating benzene in the presence of air (oxygen) and Vanadium pentoxide (V2O5V_2O_5) catalyst at 773 K—the aromatic ring undergoes cleavage.
  3. Reaction: 2C6H6+9O2→V2O5,Δ2C4H2O3 (Maleic anhydride)+4CO2+4H2O2C_6H_6 + 9O_2 \xrightarrow{V_2O_5, \Delta} 2C_4H_2O_3 \text{ (Maleic anhydride)} + 4CO_2 + 4H_2O
  4. Conclusion: The specific product formed in this catalytic vapour phase oxidation is Maleic anhydride .

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Hydrocarbons. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYHydrocarbonsoxidationbenzenepresenceproduces

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A.Option 1 (Structure missing)
B.Option 2 (Structure missing)
C.Option 3 (Structure missing)
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A.(Option 1 Structure Missing)
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