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NEET CHEMISTRYElectrochemistryMedium

Question

The weight of silver (atomic weight = 108108) displaced by a quantity of electricity which displaces 5600 mL5600 \text{ mL} of O2\text{O}_2 at STP will be :

A

5.4 g5.4 \text{ g}

B

10.8 g10.8 \text{ g}

C

54.0 g54.0 \text{ g}

D

108.0 g108.0 \text{ g}

Step-by-Step Solution

At STP, the molar volume of an ideal gas is 22400 mL/mol22400 \text{ mL/mol}. Moles of O2\text{O}_2 displaced = 5600 mL22400 mL/mol=0.25 mol\frac{5600 \text{ mL}}{22400 \text{ mL/mol}} = 0.25 \text{ mol}.

The half-reaction for the liberation of O2\text{O}_2 is: 2H2OO2+4H++4e2\text{H}_2\text{O} \rightarrow \text{O}_2 + 4\text{H}^+ + 4e^- This shows that 1 mole1 \text{ mole} of O2\text{O}_2 gas is produced by the passage of 4 moles4 \text{ moles} of electrons (4 Faradays4 \text{ Faradays}). Therefore, the charge (QQ) required to displace 0.25 moles0.25 \text{ moles} of O2=0.25×4=1 Faraday\text{O}_2 = 0.25 \times 4 = 1 \text{ Faraday}.

The half-reaction for the deposition of silver is: Ag++eAg\text{Ag}^+ + e^- \rightarrow \text{Ag} This shows that 1 Faraday1 \text{ Faraday} of electricity deposits 1 mole1 \text{ mole} of Ag\text{Ag}. Mass of 1 mole1 \text{ mole} of Ag=108 g\text{Ag} = 108 \text{ g}.

Thus, the weight of silver displaced by 1 Faraday1 \text{ Faraday} of electricity is 108.0 g108.0 \text{ g}.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Electrochemistry. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYElectrochemistryweightsilveratomicweightdisplaced

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