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NEET CHEMISTRYHydrocarbonsMedium

Question

When subjected to ozonolysis, which compound results in the formation of the given molecule?

A

(Structure Missing)

B

(Structure Missing)

C

4

D

(Structure Missing)

Step-by-Step Solution

  1. Reaction Principle: Ozonolysis is a reaction used to locate the position of the double bond in unsaturated compounds. Alkenes react with ozone to form an ozonide, which upon cleavage with Zinc (ZnZn) and water (H2OH_2O) yields smaller molecules, typically aldehydes or ketones [NCERT 11th, Ch 13, Sec 13.3.5].
  2. Mechanism: The reaction involves the oxidative cleavage of the C=CC=C double bond. The net result is the replacement of the C=CC=C bond with two C=OC=O bonds. R1CH=CHR2+O3→Zn/H2OR1CHO+R2CHOR_1CH=CHR_2 + O_3 \xrightarrow{Zn/H_2O} R_1CHO + R_2CHO
  3. Reverse Process: To find the starting alkene from the product(s), one removes the oxygen atoms from the carbonyl groups of the products and joins the carbonyl carbons with a double bond.
  4. Missing Data: The question refers to a specific "given molecule" (product) and asks for the reactant (Option). As the chemical structures for both the target molecule and the options are missing from the input text, the correct option cannot be chemically derived.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Hydrocarbons. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYHydrocarbonssubjectedozonolysiscompoundresultsformation

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Phenylacetylene undergoes a reaction with dilute $\text{H}_2\text{SO}_4$ in the presence of $\text{HgSO}_4$ to yield:

A.Option 1 (Structure missing)
B.Option 2 (Structure missing)
C.Option 3 (Structure missing)
D.Option 4 (Structure missing)
MediumSolve

The reaction among the following that proceeds through an electrophilic substitution reaction is:

A.(Option 1 Structure Missing)
B.(Option 2 Structure Missing)
C.4
D.(Option 4 Structure Missing)
EasySolve

The order of decreasing reactivity towards an electrophilic reagent for the following compounds is: (i) Benzene (ii) Toluene (iii) Chlorobenzene (iv) Phenol

A.(i) > (ii) > (iii) > (iv)
B.(ii) > (iv) > (i) > (iii)
C.(iv) > (iii) > (ii) > (i)
D.(iv) > (ii) > (i) > (iii)
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X and Y in the above-mentioned reaction are respectively:

A.X = 2–Butyne; Y = 3–Hexyne
B.X = 2-Butyne; Y = 2-Hexyne
C.X = 1-Butyne; Y = 2-Hexyne
D.X = 1-Butyne; Y = 3–Hexyne
MediumSolve

Match the bond line structures of hydrocarbons given in List-I with the corresponding boiling points given in List-II. List-II (Boiling point in K): (i) 300.9 (ii) 282.5 (iii) 309.1 (iv) 341.9 Choose the correct answer from the options given below:

A.(a)-(i), (b)-(iv), (c)-(iii), (d)-(ii)
B.(a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
C.(a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
D.(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
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The dihedral angle of the least stable conformer of ethane is:

A.$60^{\circ}$
B.$0^{\circ}$
C.$120^{\circ}$
D.$180^{\circ}$
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Phenanthrene is an aromatic compound and follows Hückel's $(4n+2)\pi$ electron rule. The value of $n$ is:

A.0
B.1
C.2
D.3
MediumSolve

The correct statement regarding the comparison of staggered and eclipsed conformations of ethane is:

A.The eclipsed conformation of ethane is more stable than staggered conformation because eclipsed conformation has no torsional strain.
B.The eclipsed conformation of ethane is more stable than staggered conformation even though the eclipsed conformation has a torsional strain.
C.The staggered conformation of ethane is more stable than eclipsed conformation because staggered conformation has no torsional strain.
D.The staggered conformation of ethane is less stable than eclipsed conformation because staggered conformation has a torsional strain.
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