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NEET CHEMISTRYSolutionsEasy

Question

Which of the following contains 0.5 moles of a solute in one molal solution?

A

1000 g of solvent

B

500 mL of solvent

C

500 g of solvent

D

100 mL of solvent

Step-by-Step Solution

Molality (mm) is defined as the number of moles of solute dissolved per kilogram (1000 g) of the solvent . Molality (m)=Moles of soluteMass of solvent in kg\text{Molality (m)} = \frac{\text{Moles of solute}}{\text{Mass of solvent in kg}} Given: Molality (mm) = 1 m=1 mol kg11 \text{ m} = 1 \text{ mol kg}^{-1} Moles of solute (nn) = 0.5 mol0.5 \text{ mol} Substituting the values: 1=0.5Mass of solvent in kg1 = \frac{0.5}{\text{Mass of solvent in kg}} Mass of solvent in kg=0.5 kg\text{Mass of solvent in kg} = 0.5 \text{ kg} Since 1 kg=1000 g1 \text{ kg} = 1000 \text{ g}, the mass of the solvent is 0.5×1000 g=500 g0.5 \times 1000 \text{ g} = 500 \text{ g}.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Solutions. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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